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Q.

If α,β are the roots of ax2+bx+c=0 then Ltx→α1+ax2+bx+c1x−α is

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a

aα−β

b

logaα−β

c

eaα−β

d

aα+β

answer is C.

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Detailed Solution

G.L=Ltex→αax2+bx+cx−α=Ltex→aax−αx−βx−α=ea⋅α−β
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