If α,β are the roots of ax2+c=bx, then the equation (a+cy)2=b2y in y has the roots

ax2−bx+c=0α+β=ba,αβ=ca Also,  (a+cy)2=b2y⇒c2y2−b2−2acy+a2=0Divide by a2⇒ca2y2−ba2−2cay+1=0      α+β2-2αβ=α2+β2⇒ (αβ)2y2−α2+β2y+1=0Divide by α2β2⇒ y2−α−2+β−2y+α−2β−2=0⇒ y−α−2y−β−2=0 Hence roots are α−2,β−2.