If α,β  are the roots of x2−p(x+1)+c=0,  then (1+α)(1+β) =

The given equation is x2−p(x+1)+c=0 ⇒x2−px−p+c=0 α,β  are the given rootsSum of the roots :  α+β=p Product of the roots : αβ=−p+c ∴(1+α)(1+β)=1+(α+β)+αβ                                =1+p−p+c=1+c