If α,β are roots x2+px+q=0, then value
of α3+β3 is
3pq+p3
3pq−p3
3pq
p3−3pq
α+β=−p,αβ=q
Now, α3+β3=(α+β)3−3αβ(α+β)
=−p3+3pq=3pq−p3