If α, β and γ are the roots of x3+8=0, then the equation whose roots are α2, β2 and γ2 is
x3-8=0
x3-16=0
x3+64=0
x3-64=0
Let y=x2. Then x=y
∴x3+8=0⇒y3/2+8=0
⇒y3=64⇒y3-64=0
Thus the equation having roots α2, β2 and γ2 is x3-64=0