If α, β are the roots of x2−3x+a=0, a∈R and α<1<β, then
a∈(−∞, 2)
a∈(−∞, 9/4]
a∈(2, 9/4]
none of these
Let f(x)=x2−3x+a. Clearly, y=f(x) represents a parabola opening upward
It is give that 1 lies between the roots of f(x)=0
Discriminant >0 and f(1)<0
⇒ 9−4a>0 and 1−3+a<0
⇒ a<94 and a<2⇒a<2⇒a∈(−∞, 2)