If α,β  are the roots of x2+x−2=0,  then α3β+αβ3 =

The given equation is x2+x−2=0 α,β  are the given rootsSum of the  roots : α+β=−1,      Product of the roots : αβ=−2 ∴α3β+αβ3=αβ(α2+β2)                          =αβ[(α+β)2−2αβ]                          =−2(1+4)=−10