If α,βare the roots of (x−a)(x−b)+c=0,
c≠0 ,then roots of (αβ−c)x2+(α+β)x+1=0 are
1/a, 1/b
– 1/a, – 1/b
1/a, –1/b
–1/a, 1/b
α,β are roots of x2−(a+b)x+ab+c=0
∴ α+β=a+b,αβ=ab+c
The equation
(αβ−c)x2+(α+β)x+1=0
becomes
abx2+(a+b)x+1=0⇒ (ax+1)(bx+1)=0⇒ x=−1/a,−1/b