If α,β and γ are roots of 4x3+8x2−x−2=0, then the  value of 4(α+1)(β+1)(γ+1)αβγ is

4x3+8x2−x−2=4(x−α)(x−β)(x−γ) Putting x=−1, we get 3=4(−1−α)(−1−β)(−1−γ) or  (α+1)(β+1)(γ+1)=−34 Also,  αβγ=12∴ 4(α+1)(β+1)(γ+1)αβγ=−6