If α,  β , 1 are roots of x3−2x2−5x+6=0 (α > 1)  then 3α+ β =

The given equation is x3−2x2−5x+6=0 Given that α,  β ,1 are the rootsTake the coefficients of given equation,And Synthetic division1  1−2−5601−1−6     1  −1    −6     0We get,  x2−x−6=0⇒(x−3)(x+2) = 0⇒α=3,β=−2∴3α+β=7