If 8, 2 are the roots of x2+ax+β=0 and 3, 3 are the roots of x2+αx+b=0, then the roots of x2+ax+b=0 are

8, 2 are the roots of x2+αx+β=0∴8+2=10=-a, 8.2=16=β i.e. α=-10, β=163, 3 are the roots of x2+αx+b=0∴3+3=6=-α, 3.3=b i.e. α=-6, b=9Now, x2+ax+b=0 becomes x2-10+9=0or (x-1)(x-9)=0⇒x=1, 9.