If 1,2,3  are the roots of x3+ax2+bx+c=0 , then (a,b,c)=

The given equation is x2+ax2+bx+c=0   1,2,3  are the roots of given equations1:1+2+3=−a⇒a=−6 s2:1(2)+2(3)+3(1)=b⇒b=11 s3:(1)(2)(3)=−c⇒c=−6 ∴(a,b,c)=(−6,11,−6) Hence (1) is correct choice.