If α, β are roots of x2-3x+1=0, then the equation whose roots are 1α-2, 1β-2 is

α, β are the roots of the equation x2-3x+1=0∴ α+β=3 and αβ=1S=1α-2+1β-2=α+β-4αβ-2(α+β)+4=3-41-2.3+4=1and P=1(α-2)(β-2)=1αβ-2(α+β)+4=-1Hence the equation whose roots are 1α-2 and 1β-2 are x2-Sx+P=0⇒x2-x-1=0