If αand β are two roots of the equation x2−64x+256=0 Then, value of α3β51/8+β3α51/8 is
Given quadratic equation x2−64x+256=0 having roots αand β , so
α+β=64 and αβ=256
now,
α3β51/8+β3α51/8=α+βαβ58=6425=6432=2