Q.

If αand β are two roots of the equation x2−64x+256=0 Then, value of α3β51/8+β3α51/8 is

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answer is 2.

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Detailed Solution

Given quadratic equation x2−64x+256=0 having roots αand β , soα+β=64 and αβ=256now,α3β51/8+β3α51/8=α+βαβ58=6425=6432=2
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If αand β are two roots of the equation x2−64x+256=0 Then, value of α3β51/8+β3α51/8 is