First slide
Multiple and sub- multiple Angles
Question

If θ1 and θ2 are two values lying in  [0,2π] for which tanθ=λ, then tanθ12tanθ22 is equal to

Moderate
Solution

tanθ=λ  we get  2tanθ/21tan2θ/2=λ

 or  λtan2θ2+2tanθ2λ=0 tanθ12tanθ22=1
 

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