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If the area of the circle
$4 x^{2} + 4 y^{2} - 8 x + 16 y + k = 0$ is $9 π$
square units, then the value of $k$ is

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Correct option is C

We have,4x2+4y2−8x+16y+k=0⇒x2+y2−2x+4y+k4=0The radius of this circle is 1+4−k4=20−k2We have,Area of the circle = 9π square units⇒π20−k4=9π⇒k=−16

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If the area of the circle 4x2+4y2−8x+16y+k=0 is 9πsquare units, then the value of k is

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Ready to Test Your Skills?

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If the area of the circle
$4 x^{2} + 4 y^{2} - 8 x + 16 y + k = 0$ is $9 π$
square units, then the value of $k$ is