If  the area of the triangle formed by the positive x-axis, the normal and the tangent to the circle x−22+y−32=25 at the point 5,7  is A, then 24A is equal to

Equation of the curve is x−22+y−32=25The value of dydx at 5,7 is 2x-2+2y-3dydx=0⇒23+24dydx=0⇒dydx=-34 The area of the triangle required is 12length of the tangentlength of the normal =12y12×1+m2m =1249×1+91634=12252424A=1225