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Questions  

 If the arithmetic mean of the numbers x1,x2,x3,,xk is x¯ then the arithmetic mean of the numbers 

 ax1+b,ax2+b,ax3+b..........axn+b,

where a,b are two constants, would be 

a
x
b
nax+nb
c
ax
d
ax+b

detailed solution

Correct option is D

Required mean is  ax1+b+ax2+b+⋯+axn+bn  =ax1+x2+⋯+xnn+b=ax¯+b ∵x1+x2+⋯+xnn=x¯

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