If the arithmetic mean of the observations x1,x2,x3,…,xn is 1, then the arithmetic mean of x1k,x2k,x3k,…,xnk (k>0), is

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greater than l

less than l

equal to 1

none of these

answer is D.

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Detailed Solution

We have,x1+x2+x3+…+xnn=1⇒x1+x2+x3+…+xn=n∴ Required arithmetic mean =x1k+x2k+….+xnkn =1kx1+x2+…+xnn=1k

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