If the arithmetic mean of the observations $$x1$$,$$x2$$,$$x3$$,…,xn is $$1$$, then the arithmetic mean of $$x1k$$,$$x2k$$,$$x3k$$,…,xnk (k$$>$$0), is

Correct option is 4none of these

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If the arithmetic mean of the observations $x_{1}, x_{2}, x_{3}, \dots, x_{n}$ is $1,$ then the arithmetic mean of $\frac{x_{1}}{k}, \frac{x_{2}}{k}, \frac{x_{3}}{k}, \dots, \frac{x_{n}}{k}$ $(k > 0),$ is

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Correct option is D

We have,x1+x2+x3+…+xnn=1⇒x1+x2+x3+…+xn=n∴ Required arithmetic mean =x1k+x2k+….+xnkn =1kx1+x2+…+xnn=1k

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Variate x	1	2	3	4	5
Frequency f of x	4	5	y	1	2

If the arithmetic mean of the observations x1,x2,x3,…,xn is 1, then the arithmetic mean of x1k,x2k,x3k,…,xnk (k>0), is

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If the arithmetic mean of the observations $x_{1}, x_{2}, x_{3}, \dots, x_{n}$ is $1,$ then the arithmetic mean of $\frac{x_{1}}{k}, \frac{x_{2}}{k}, \frac{x_{3}}{k}, \dots, \frac{x_{n}}{k}$ $(k > 0),$ is