If ax2+bx+c=0, then x=
b±b2-4ac2a
-b±b2-ac2a
2c-b±b2-4ac
None of these
x=-b±b2-4ac2a
Since 2c-b+b2-4ac.-b-b2-4ac-b-b2-4ac
=2c(-b-b2-4ac)4ac=-b-b2-4ac2a
Similarly 2c-b-b2-4ac×-b+b2-4ac-b+b2-4ac
=2c(-b+b2-4ac)4ac=-b+b2-4ac2a