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If ${ax}^{3} + {bx}^{2} + cx + d$ is divisible by ${ax}^{2} + c$ ,then a, b, c, d are in

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Correct option is B

Since, ax3+bx2+cx+d is divisible by ax2+c.Therefore, when ax3+bx2+cx+d is divided by al + c, the remainder is zero∴ d−bca=0⇒ bc=ad⇒ba=dc⇒a,b,c,d are in GP.

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If ax3+bx2+cx+d is divisible by ax2+c,then a, b, c, d are in

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If ${ax}^{3} + {bx}^{2} + cx + d$ is divisible by ${ax}^{2} + c$ ,then a, b, c, d are in