If ax2+cy+a′x2+c′=0and x is a rational function of y and ac is negative, then
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a
ac′+a′c=0
b
aa′=cc′
c
a2+c2=a2+c2
d
aa′+cc′=1
answer is B.
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Detailed Solution
Given, ax2+cy+a′x2+c′=0or x2ay+a′+cy+c′=0If x is rational, then the discriminant of the above equation must be a perfect square. Hence, 0−4ay+a′cy+c′must be a perfect square⇒ −acy2−ac′+a′cy−a′c′ must be a perfect square⇒ ac′+a′c2−4ac⋅a′c′=0 [∵D=0]⇒ ac′−a′c2=0⇒ ac′=a′c⇒ aa′=cc′