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If $(1 + ax)^{n} = 1 + 8 x + 24 x^{2} + \dots, t$ then the values of $a$ and $n$ are

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Correct option is A

Given that, (1+ax)n=1+8x+24x2+… 1+n1ax+n(n−1)1⋅2a2x2+…=1+8x+24x2+…On comparing the coefficients of x,x2 we getna=8,n(n−1)1⋅2a2=24⇒ na(n−1)a=48⇒ 8(8−a)=48⇒ 8−a=6⇒a=2⇒ n=4

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If (1+ax)n=1+8x+24x2+…,t then the values of a and n are

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If $(1 + ax)^{n} = 1 + 8 x + 24 x^{2} + \dots, t$ then the values of $a$ and $n$ are