If a(α→×β→)+b(β→×γ→)+c(γ→×α→)=0 and at least one of a, b and c is non-zero, then vectors α→,β→ and γ→ are
parallel
co-planar
mutually perpendicular
none of these
Taking dot Product of a(α→×β→)+b(β→×γ→)+c(γ→×α→)=0 with α→,β→ and γ→ respectively
we have,
a[α→β→γ→]=0
b[α→β→γ→]=0c[α→β→γ→]=0
Since at least one of a, b and c ≠ 0, we have
[α→β→γ→]=0
Hence, α→,β→ and γ→ are co-planar.