If a and b arc positive numbers and each of the equations x2+ax+2b=0 and x2+2bx+a=0 has real roots, then the smallest possible value of (a + b) is _________.
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answer is 6.
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Detailed Solution
a2≥8b and 4b2≥4aNow b2≥a⇒ b4≥a2≥8b (a>0,b>0)∴ b3≥8⇒b≥2 (1)Again a2≥8b and b≥2⇒ a2≥16 or a≥4 (2)From (1) and (2), (a+b)least =6.