If a→ and b→ are any two vectors of magnitudes 2 and 3, respectively, such that |2(a→×b→)|+|3(a→⋅b→)|=k then the maximum value of k is
13
213
613
1013
k=|2(a→×b→)|+|3(a→⋅b→)| =12sinθ+18cosθ⇒ Maximum value of k=122+182=613