If A and B are coefficients of xr and xn-r respectively in the expansion of (1+x)n, then
A=B
A+B=0
A=rB
A=nB
We have,
A = Coeff. of xr in the expansion of (1+x)n=nCr
B = Coeff. of xn-r in the expansion of (1+x)n=nCn−r
∵ nCr=nCn−r ∴A=B