Q.

If A and B are conjugate points w.r.t to circle x2+y2=r2 then OA2+OB2=

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a

AB2−r2

b

AB2+r2

c

AB2+2r2

d

AB2−2r2

answer is C.

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Detailed Solution

A(x1,y1)  B(x2,y2)  are conjugate points ⇒x1x2+y1y2=r2 ∴OA2+OB2−2r2=AB2
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