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Q.

If A and B are events such that P(A) =p1 , P(B)= p2  and P(A∩B)=p3  then P(A¯∪B)=

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a

1−p1+p2

b

1−p1+p3

c

1−p1−p2

d

p1+p2−1

answer is B.

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Detailed Solution

P(A¯∪B)=P(A¯)+P(B)−P(A¯∩B)                     =1−P(A)+P(B)−{P(B)−P(A∩B)}                     =1−P(A)+P(A∩B)                     =1−p1+p3
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