First slide

Operations on Sets

Question

If A and B are not disjoint sets, then $n (A \cup B)$ is equal to

Easy

A

$n (A) + n (B)$
B

$n (A) + n (B) - n (A \cap B)$
C

$n (A) + n (B) + n (A \cap B)$
D

$n (A) n (B)$

Solution

$n (A \cup B) = n (A) + n (B) - n (A \cap B) .$

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