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Questions  

If A and B are square matrices of same order such that (A + B)2 = A2 + B2 + 2AB, then

a
AB = BA
b
A = B
c
A = B'
d
A = -B

detailed solution

Correct option is A

We have,(A + B)2 = A2 + B2 + 2AB⇒ (A + B) (A + B) = A2 + B2 + 2AB⇒ A2 + AB + BA + B2 =A2 + B2 + 2AB⇒ BA = AB

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