If A and B are square matrices of same order such that (A + B)2 = A2 + B2 + 2AB, then
AB = BA
A = B
A = B'
A = -B
We have,(A + B)2 = A2 + B2 + 2AB⇒ (A + B) (A + B) = A2 + B2 + 2AB⇒ A2 + AB + BA + B2 =A2 + B2 + 2AB⇒ BA = AB