if A (2,– 1) and B (6, 5) are two points. The ratio in which the foot of the perpendicular from (4, 1) to AB divides it

Eqn of AB                               y+1=5+16−2(x−2)                ⇒y+1=32(x−2)                ⇒3x−2y−8=0 ----(1)foot of the perpendicular from (4,1) to equation (1) is                 h−43=k−1−2=−(12−2−8)9+4                ⇒h=4613                ratio =x1−x:x−x2                =(2−4613):(4613−6)                =5  :  8