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If Aand B are two sets such that n(A∪B)=36, n(A∩B)=16 and n(A~B)=15, then n(B) is equal to

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a

21

b

31

c

20

d

52

answer is A.

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Detailed Solution

n(A~B)=n(A)−n(A∩B)⇒15=n(A)−16⇒n(A)=31n(A∪B)=n(A)+n(B)−n(A∩B)⇒36=31+n(B)−16⇒ n(B)=21.

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