First slide
Theory of equations
Question

If b1b2=2(c1+c2), then at least one of the equations x2+b1x+c1=0 and x2+b2x+c2=0 has

Moderate
Solution

Let D1 and D2 be discriminants of x2+b1x+c1=0

and x2+b2x+c2=0 respectively. Then

D1+D2=b12-4c1+b22-4c2=(b12+b22)-4(c1+c2) b12+b22-2b1b2,     (b1b2=2(c1+c2)) =(b1-b2)20 D10 or D20 or D1 and D2 both are positive.

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