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Q.

If a≠b,b≠c, if ax+by+c=0, bx+cy+a=0 and cx+ay+b=0 are concurrent. The the value of 2a2b−1c−12b2c−1a−12c2a−1b−1

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a

2

b

4

c

6

d

8

answer is D.

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Detailed Solution

a+b+c=0;a3+b3+c3=3abc
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