If A(1,2,3),B(2,3,4)and AB is produced up to Csuch that 2AB=BC, then C=
(5,4,6)
(4,1,4)
52,72,92
(4,5,6)
Given 2AB=BC
it gives
AB¯=BC¯ 2(OB¯−OA¯)=(OC¯−OB¯)2OB¯−2OA¯+OB¯=OC¯OC¯=3OB¯−2OA¯
It implies
OC¯=3(2i+3j+4k)−2(i+2j+3k)=6i+9i+12k−2i−4j−6k=4i+5j+6k
Therefore, C(4,5,6)