First slide

Operations of matrix

Question

If $A - 2 B = [\begin{array}{ll} 1 5 \\ 3 7 \end{array}]$ and $2 A - 3 B = [\begin{array}{rr} - 2 5 \\ 0 7 \end{array}]$ , then matrix B is equal to

Easy

A

$[\begin{array}{ll} - 4 - 5 \\ - 6 - 7 \end{array}]$
B

$[\begin{array}{rr} 0 6 \\ - 3 7 \end{array}]$
C

$[\begin{array}{rr} 2 - 1 \\ 3 2 \end{array}]$
D

$[\begin{array}{rr} 6 - 1 \\ 0 1 \end{array}]$

Solution

We have
$B = (2 A - 3 B) - 2 (A - 2 B) = [\begin{array}{rr} - 4 - 5 \\ - 6 - 7 \end{array}]$

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