If A, B, C are the angles of a triangle such that cotA2=3 tanC2, then sin A, sin B, sin C are in
A.P
G.P.
H.P
none of these
Given cotA2⋅cotC2=3⇒cosA2⋅cosC2sinA2⋅sinC2=3⇒cosA−C2cosA+C2=2 (using componendo and dividendo)⇒2sinA+C2cosA−C22sinA+C2⋅cosA+C2=2⇒2sinB=sinA+sinC