If A, B, C are collinear points such thatA(−1,1),B(0,−2)  and AC=10,  then C=

A(−1,1),B(0,−2)         AB=1+9=10 AC=10 A is the mid pt of B,C ⇒  B+C=2A ⇒ C=2A–B =(−2,2)−(0,−2)=(−2,4)