If a, b, c are consecutive positive integers and 1og ( 1 + ac) =2K, then the value of K is
log b
log a
2
1
Let a=x−1,b=x,c=x+1
Now log(1+ac)=log[1+(x−1)(x+1)]=logx2=2logx=2logb⇒ K=logb