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If a, b and c are the greatest values of , and respectively, then:
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a
a11=b22=c21
b
a11=b22=c42
c
a10=b11=c42
d
a10=b11=c21
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Correct option is B
We know Cn2 n(if n is even) and Cn-12 nor Cn+12 n (if n is odd) are greatest at middle term(s)∴a=Cp 19=C10 19=C9 19and b=Cq 20=C10 20and c=Cr 21=C10 21=C11 21Now, using Cr nCr−1 n−1=nr , we get aC9 19=b2010.C9 19=c2111.2010C9 19⇒a1=b2=c4211⇒a11=b22=c42Similar Questions
is equal to
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