If a, b, and c are in H.P., then the value of (ac+ab−bc)(ab+bc−ac)(abc)2 is
(a+c)(3a−c)4a2c2
2bc−1b2
2bc−1a2
(a−c)(3a+c)4a2c2
1b+1c−1a1c+1a−1b=1b+1c−2b+1c1c+1b−1c=2c−1b1b=2bc−1b2
Also by eliminating b, we get the given expression
(a+c)(3a−c)4a2c2.