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If a,b and c  are non-coplanar vectors a×c is perpendicular to a×(b×c)  then the value of [a×(b×c)]×c is equal to

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a
[a→b→c→]c→
b
[a→b→c→]b→
c
-[a→b→c→]a→
d
0→

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detailed solution

Correct option is D

Given that   a→,b→ and c→  are non-coplanar vectors  Thus, [a→b→c→]≠0----iagain a→×(b→×c→)⋅(a→×c→)=0or  [(a→⋅c→)b→−(a→⋅b→)c→]⋅(a→×c→)=0or  (a→⋅c→)[b→a→c→]=0or  (a→⋅c→)=0 Hence, a→ and c→ are perpendicular. ---iia→×(b→×c→)=(a→⋅c→)b→−(a→⋅b→)c→or   [a→×(b→×c→)]×c→=0→


Similar Questions

Let a,b and c be three non-coplanar vectors and r be any arbitrary vector. Then (a×b)×(r×c)+(b×c)×(r×a)+(c×a)×(r×b) i, always equal to


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