First slide
Theory of expressions
Question

 If a,b, and c are not all equal and α and β

 be the roots of the equation ax2+bx+c=0, then value of 

1+α+α21+β+β2 is 

Moderate
Solution

 We have α+β=b/a,αβ=c/a

Now,    1+α+α21+β+β2         =1+α+β+α2+β2+αβ+α2β+αβ2+α2β2         =1+(α+β)+(α+β)22αβ+αβ[1+α+β+αβ]         =1ba+b2a22ca+ca+caba+c2a2         =1a2a2+b2+c2bccaab         =12a2(bc)2+(ca)2+(ab)20

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