If a,b and c are in A.P, and b−a,c−b and a are in G.P, then a:b:c is
1:2:3
1:3:5
2:3:4
1:2:4
We have, 2b=a+c(c−b)2=(b−a)a⇒(b−a)2=(b−a)a [2b=a+c⇒b−a=c−b]⇒b=2a⇒c=3a [ using 2b=a+c]⇒a:b:c=1:2:3