If a,b,c are in A.P., b,c,d are in G.P. and c,d,e are in H.P. then a,c,e are in

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A.P

G.P

H.P

None

answer is B.

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Detailed Solution

Given a,b,c are in AP ⇒2b=a+cGiven b,c,d are in GP ⇒c2=bdGiven c,d,e are in HP ⇒d=2cec+ea+c2⋅2cec+e=bd=c2a+ce=cc+eae+ce=c2+ceae=c2a,c,e are in GP

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