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If A, B, C are in A.P and $B = \frac{π}{4}$ then $\tan A \tan B \tan C =$

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Correct option is A

We have 2B=A+C and B=π4⇒tan2B=tanA+tanC1-tanA·tanCBut tan2B=tanπ2=not defined⇒1-tanAtanC=0⇒tanAtanC=1∴ tanAtanBtanC=1 ∵tanB=tanπ4=1

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If A, B, C are in A.P and B=π4 then tanAtanBtanC=

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If A, B, C are in A.P and $B = \frac{π}{4}$ then $\tan A \tan B \tan C =$