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If $a, b, c$ are in A.P., a, x, b are in G.P. and b, y, c are in G.P., the point (x, y) lies on

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Correct option is B

We have 2b=a+c,x2=ab,y2=bc so that x2+y2=b(a+c)=2b2 which is a circle.

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If a,b,c are in A.P., a, x, b are in G.P. and b, y, c are in G.P., the point (x, y) lies on

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If $a, b, c$ are in A.P., a, x, b are in G.P. and b, y, c are in G.P., the point (x, y) lies on