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If $a, b, c$ are in A.P., and $Δ = |\begin{array}{ccc} x + 2 & x + 7 & a \\ x + 5 & x + 11 & b \\ x + 8 & x + 15 & c \end{array}|$ then $∆$ equals

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– (a + b + c)

a + b + c.

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Correct option is A

Use R1→R1+R3−2R2Δ=x+2x+7ax+5x+11bx+8x+15c =000x+5x+11bx+8x+15c=0

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If a, b, c are in A.P., and Δ=x+2x+7ax+5x+11bx+8x+15c then ∆ equals

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

If $a, b, c$ are in A.P., and $Δ = |\begin{array}{ccc} x + 2 & x + 7 & a \\ x + 5 & x + 11 & b \\ x + 8 & x + 15 & c \end{array}|$ then $∆$ equals