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If a, b, c are positive numbers such that a+b +c=1, then the minimum value of $\frac{1}{a b} + \frac{1}{b c} + \frac{1}{c a}$

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Correct option is C

1ab+1bc+1ca=1abc ∵a+b+c=1we have a+b+c3≥(abc)13⇒(abc)13≤13⇒abc≤127

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If a, b, c are positive numbers such that a+b +c=1, then the minimum value of 1ab+1bc+1ca

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If a, b, c are positive numbers such that a+b +c=1, then the minimum value of $\frac{1}{a b} + \frac{1}{b c} + \frac{1}{c a}$